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Home » Top 10 WWII Posters That Influenced History—Shocking Secrets You’ll Want to Share! - Appcentric

Top 10 WWII Posters That Influenced History—Shocking Secrets You’ll Want to Share! - Appcentric

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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📌 So it reaches 1000 atm during ascent at ~7300 meters. But question asks for depth before reaching — so maximum depth where it's ≤1000.

📌 Since 72.45 × 100 = 7245, check:

📌 \( (1.1)^{72.45} = 1000 \) → depth = 7245 m exceeds, so first depth where it exceeds is 7245 m. But we want when it first reaches or exceeds — so depth = 7245 m. However, for precision in math context without trig, and aligning with format, use:

📌 Depth = \( 100 \times \log_{1.1}(1000) \approx 7245 \), but since percentages are discrete, and question implies exact threshold, but in applied context, use rounded value.

📌 But per format, expect numerical answer:

📌 Final answer based on exact calculation:

📌 \( \boxed{7245} \) (meters, rounded to nearest 100 m where it exceeds) — but to match precision, accept:

📌 Actually, solving \( 1.1^d / 100? \) no — depth is in 100m units: let \( d \) = number of 100m units.

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Question: Define $ L(u) = u - \frac{u^3}{3} $ for every real number $...
a_n = \sum_{k=1}^{n} L\left(\frac{k}{n}\right)
Find $ \lim_{n \to \infty} a_n $.
L(u) = u - \frac{u^3}{3}, \quad a_n = \sum_{k=1}^{n} L\left(\frac{k}{n...
\lim_{n \to \infty} a_n = \lim_{n \to \infty} \sum_{k=1}^{n} \left( \f...
This is a Riemann sum. Split the sum:
a_n = \sum_{k=1}^{n} \frac{k}{n} - \frac{1}{3} \sum_{k=1}^{n} \left( \...
= \frac{1}{n} \sum_{k=1}^{n} k - \frac{1}{3n^3} \sum_{k=1}^{n} k^3
Use formulas:
$ \sum_{k=1}^{n} k = \frac{n(n+1)}{2} $

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\[ x = \frac{27}{11}, \quad y = \frac{26}{11} \]
#### \(\left(\frac{27}{11}, \frac{26}{11}\right)\)
\(\log_2(x) + \log_2(x - 2) = 3\) のとき、\(x\) の値を求めなさい。
\[ \log_2(x) + \log_2(x - 2) = \log_2[x(x - 2)] \]
\[ \log_2[x(x - 2)] = 3 \]
\[ x(x - 2) = 2^3 = 8 \]
\[ x = \frac{2 \pm \sqrt{(-2)^2 - 4(1)(-8)}}{2(1)} = \frac{2 \pm \sqrt...
\[ x = \frac{8}{2} = 4 \quad \text{or} \quad x = \frac{-4}{2} = -2 \]
\(x > 2\)（対数の定義域より）なので、\(x = 4\)
一辺の長さ \(s = 6\) の正三角形の面積は：

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