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Thus, the energy values are: - Appcentric

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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Now check the numerator at $ t = 2 $:
t^2 + 1 = 4 + 1 = 5
Since the numerator is not zero when $ t = 2 $, and the denominator is...
oxed{ ext{Vertical asymptote at } t = 2; ext{ no holes} }
Question: A robotics engineer uses the function $ f(x) = \sqrt{x + 3}...
Solution: First, evaluate $ f(6) $:
f(6) = \sqrt{6 + 3} = \sqrt{9} = 3
Now compute $ g(f(6)) = g(3) $:
g(3) = 2(3) -
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But 64,000 is not — so either error, or compute until size 1 or less,...
To fix: change to a power of 2.
But following strict math: number of times a number can be divided by...
For n = 2^k, number of times you can divide by 2 until 1 is k.
For n = 64000, k = log₂(64000) ≈ 15.965 — not integer.
But the problem likely intends a power of 2.
To resolve, assume the dataset size is 65
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