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Home » The semi-perimeter \(s\) is: - Appcentric

The semi-perimeter \(s\) is: - Appcentric

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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🔥 Popular Posts

$ f(x) = 0 $: $ f(a + b + c) = 0 = 0 + 0 + 0 = f(a) + f(b) + f(c) $, a...
$ f(x) = x $: $ f(a + b + c) = a + b + c = f(a) + f(b) + f(c) $, and $...
Are there any others? Suppose $ f $ is additive and multiplicative. Th...
If $ f(1) = 0 $, then $ f(n) = 0 $ for all integers $ n $, and by addi...
Hence, only two such functions exist.
Thus, the number of such functions is
Question: Define $ L(u) = u - \frac{u^3}{3} $ for every real number $...
a_n = \sum_{k=1}^{n} L\left(\frac{k}{n}\right)
Find $ \lim_{n \to \infty} a_n $.
L(u) = u - \frac{u^3}{3}, \quad a_n = \sum_{k=1}^{n} L\left(\frac{k}{n...

📝 Recent Posts

Solution: Let the number of shelves be \( n \). The number of panels f...
S_n = \frac{n}{2} \left(2a + (n - 1)d\right) = \frac{n}{2} \left(2(7)...
Set this equal to 150:
\frac{n}{2} (4n + 10) = 150 \implies n(4n + 10) = 300 \implies 4n^2 +...
Divide by 2: \( 2n^2 + 5n - 150 = 0 \). Use the quadratic formula:
n = \frac{-5 \pm \sqrt{5^2 - 4(2)(-150)}}{2(2)} = \frac{-5 \pm \sqrt{2...
Take the positive root: \( n = \frac{30}{4} = 7.5 \). Since \( n \) mu...
S_7 = \frac{7}{2} (4(7) + 10) = \frac{7}{2} (38) = 7 \cdot 19 = 133 \l...
\( S_8 = \frac{8}{2} (4(8) + 10) = 4 \cdot 42 = 168 > 150 \), so maxim...
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