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Home » "Head to Bedroom Fame Fast—Baby Walking Shoes That Slay Every First Step! - Appcentric

"Head to Bedroom Fame Fast—Baby Walking Shoes That Slay Every First Step! - Appcentric

📅 February 27, 2026 👤 scraface

Feb 27, 2026

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& 2 & 3 \\
\end{vmatrix} = \langle 2v_3 - 3v_2, 3v_1 - v_3, v_2 - 2v_1 \rangle =...
This yields the system:
2v_3 - 3v_2 = 4, \quad 3v_1 - v_3 = 5, \quad v_2 - 2v_1 = 6.
From the third equation, $v_2 = 6 + 2v_1$. Substituting into the first...
2v_3 - 3(6 + 2v_1) = 4 \implies 2v_3 - 18 - 6v_1 = 4 \implies 2v_3 = 2...
Substitute $v_3$ into the second equation:
3v_1 - (11 + 3v_1) = 5 \implies -11 = 5, \text{ which is a contradicti...
However, the condition $\mathbf{v} \cdot \mathbf{a} = 0$ implies $v_1...
v_1 + 2(6 + 2v_1) + 3(11 + 3v_1) = 0 \implies v_1 + 12 + 4v_1 + 33 + 9...

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-\frac{7}{6} + \frac{21}{2} - \frac{82}{3} + d = 3
-\frac{7}{6} + \frac{63}{6} - \frac{164}{6} + d = 3
-\frac{108}{6} + d = 3 \implies -18 + d = 3 \implies d = 21
Thus, the polynomial is:
f(x) = -\frac{7}{6}x^3 + \frac{21}{2}x^2 - \frac{82}{3}x + 21
\boxed{-\frac{7}{6}x^3 + \frac{21}{2}x^2 - \frac{82}{3}x + 21}
Let \( a \) and \( b \) be complex numbers such that \( a + b = 4 + 2i...
We start with the identity for the square of a sum:
Rearranging gives:
a^2 + b^2 = (a + b)^2 - 2ab

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